\(\sqrt{x^2}-8x+16=7\Leftrightarrow\left|x\right|-8x+16=7\)(1)
Nếu x\(\ge0\) thì (1)\(\Leftrightarrow x-8x+16=7\Leftrightarrow-7x=-9\Leftrightarrow x=\dfrac{9}{7}\left(tm\right)\)
Nếu x<0 thì (1)\(\Leftrightarrow-x-8x+16=7\Leftrightarrow-9x=-9\Leftrightarrow x=1\left(ktm\right)\)
Vậy S=\(\left\{\dfrac{9}{7}\right\}\)
Tìm x :
a/ \(\sqrt{x^2-8x+16}=2x-7\)
b/ \(\sqrt{4x^2-4x+1}-2=x\)
c/ \(\sqrt{x^2-8x+16}=2x+7\)
làm giúp mk nhé mn ơiiii
\(\sqrt{x^2-8x+16}=7\)
\(\sqrt{x^2-8x+16}=7\)
giải pt :
1 ) \(\sqrt{3x^2+6x+7}+\sqrt{5x^2+10x+21}=5-2x-x^2\)
2 ) \(\sqrt{4x^2+20x+25}+\sqrt{x^2-8x+16}=\sqrt{x^2+18x+81}\)
Tìm GTNN:
\(\sqrt{x^2-6x+9}+\sqrt{x^2-8x+16}\)
Tim x de bt co nghia:
\(B=\frac{\sqrt{16-x^2}}{\sqrt{2x+1}}+\sqrt{x^2-8x+8}\)
\(x^3+10-2\sqrt{2x+1}=2\left(8x+\sqrt{16-3x}\right)\)
Giải pt: \(\left(3\sqrt{x}+\sqrt{x+8}\right)\left(4+3\sqrt{x^2+8x}\right)=16\left(x-1\right)\)
giải phương trình: \(x+2\sqrt{7-x}=2\sqrt{x-1}+\sqrt{-x^2+8x-7}+1\)
