\(\dfrac{x^2-4}{x+2}=\dfrac{3x}{2}\)
\(\Leftrightarrow\dfrac{\left(x-2\right)\left(x+2\right)}{x+2}=\dfrac{3x}{2}\)
\(\Leftrightarrow x-2=\dfrac{3x}{2}\)
\(\Leftrightarrow3x=\left(x-2\right)2\)
\(\Leftrightarrow3x=2x-4\)
\(\Leftrightarrow3x-2x=-4\)
\(\Leftrightarrow x=-4\)
Vậy..
\(\dfrac{x^2-4}{x+2}=\dfrac{3x}{2}\)
\(\Leftrightarrow\dfrac{\left(x+2\right)\left(x-2\right)}{x+2}=\dfrac{3x}{2}\Leftrightarrow x-2=\dfrac{3x}{2}\)
\(\Leftrightarrow3x=2x-4\)
\(\Leftrightarrow3x-2x=-4\)
\(\Leftrightarrow x=-4\)