\(\left(8x+2\right)\left(1-3x\right)+\left(6x-1\right)\left(4x-10\right)=-50\)
\(\Leftrightarrow8x-24x^2+2-6x+24x^2-60x-4x+10=-50\)
\(\Leftrightarrow-62x+12=-50\)
\(\Leftrightarrow-62x=-62\)
\(\Leftrightarrow x=1\)
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Có (8x + 2)(1 - 3x) + (6x - 1)(4x - 10) = -50
=>8x - 24\(^{x^2}\) + 2 - 6x + 24\(^{x^2}\) - 60x - 4x + 10 = -50
=> -62x + 12 = -50
=> -62x = -62
=> x=1 (T/m)
Vậy x=a
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