Question

Phân tích đa thức thành nhân tử

x² -y² +14x + 49

x²- 24x - 25

x² -3xy

xy+xz -zy-2z

4x³ + 8x²y + 4xy² -16

3x² -18x +27

xy-y² -x+y

x² -5x+ 6

Answer 1

1 ) \(x^2-y^2+14x+49=\left(x+7\right)^2-y^2=\left(x+y+7\right)\left(x-y+7\right)\)

2 ) \(x^2-24x-25=x^2+x-25x-25=\left(x+1\right)\left(x-25\right)\)

3 ) \(x^2-3xy=x\left(x-3y\right)\)

4 ) \(xy+xz-zy-z^2=x\left(y+z\right)-z\left(y+z\right)=\left(x-z\right)\left(y+z\right)\)

5 ) \(4x^3+8x^2y+4xy^2-16=4\left(x^3+2x^2y+xy^2-4\right)\)

6 ) \(3x^2-18x+27=3\left(x^2-6x+9\right)=3\left(x-3\right)^2\)

7 ) \(xy-y^2-x+y=y\left(x-y\right)-\left(x-y\right)=\left(x-y\right)\left(y-1\right)\)

8 ) \(x^2-5x+6=x^2-2x-3x+6=\left(x-2\right)\left(x-3\right)\)