\(\sqrt[3]{3-x}+\sqrt[3]{x-1}=0\)
\(\Leftrightarrow\sqrt[3]{3-x}=-\sqrt[3]{x-1}\)
\(\Leftrightarrow3-x=1-x\)
\(\Leftrightarrow0x=2\left(voli\right)\)
Vậy \(ptvn\)
Giải pt
\(5\sqrt[3]{x+1}+1\sqrt{x+2}+5\sqrt[3]{x+3}=0\)
giải pt sau
1, \(\sqrt{5-2x}=6\)
2,\(\sqrt{2-x}-\sqrt{x+1}=0\)
3, \(\sqrt{4x^2+4x+1}=6\)
4,\(\sqrt{x^2-10x+25}=x-2\)
Giải pt 3x+x2 +7 - \(3\sqrt{x+3}-\sqrt{7x+18}\)=0
Giải pt:
a) \(\sqrt{2x^2-3}\)=\(\sqrt{4x-3}\)
b) \(\sqrt{2x-1}\)=\(\sqrt{x-1}\)
c) \(\sqrt{x^2-x-6}\)=\(\sqrt{x-3}\)
d) \(\sqrt{x^2-x}\)=\(\sqrt{3x-5}\)
Giúp em với, anh thịnh giúp em xíu á
1)giải pt: 1+\(\dfrac{2}{3}\sqrt{x-x^2}=\sqrt{x}+\sqrt{1-x}\)
2)giải pt: \(\dfrac{x^2}{\sqrt{3x-2}}-\sqrt{3x-2}=1-x\)
giải pt : \(\dfrac{1}{\sqrt{x+1}+\sqrt{x+2}}+\dfrac{1}{\sqrt{x+2}+\sqrt{x+3}}+\dfrac{1}{\sqrt{x+3}+\sqrt{x+4}}+...+\dfrac{1}{\sqrt{x+2019}+\sqrt{x+2020}}=11\)
1,
A=\(3\sqrt{8}-\sqrt{50}-\sqrt{\sqrt{2}-1}\)
B=2\(\dfrac{2}{x-1}\sqrt{\dfrac{x^2-2x+1}{4x^2}}\) với 0<x<1
2,Giải pt
\(\sqrt{x^2-3x+2}+\sqrt{x+2}=\sqrt{x+2}+\sqrt{x^2+2x+3}\)
Giải pt: \(\sqrt[3]{\left(x-1\right)^2}-\sqrt[3]{\left(x+1\right)^2}=2\sqrt[3]{x^2-1}\)
Giải pt
a.\(\sqrt[3]{1-x}+\sqrt{x+2}=1\)
b.\(\sqrt[3]{7x+1}-\sqrt[3]{x^2-x-8}+\sqrt[3]{x^2-8x-1}=2\)
