Question

Viết biểu thức sau dưới dạng bình phương của 1 biểu thức:

a. \(16x^2+8x+1\)

b.\(x^2-x+\dfrac{1}{4}\)

c.\(x^2+3x+\dfrac{9}{4}\)

d.\(x^2-\dfrac{5}{2}x+\dfrac{25}{16}\)

e.\(\dfrac{9}{4}x^2-\dfrac{6}{5}x+\dfrac{4}{25}\)

g. \(x^2y^2+2xy+1\)

h.\(x^2+10x+25\)

i.\(-x^2+12x-36\)

k.\(-4x^2-12x-9\)

Answer 1

a , \(16x^2+8x+1=\left(4x\right)^2+2.4x.1+1^2=\left(4x+1\right)^2\)

b , \(x^2-x+\dfrac{1}{4}=x^2-2.x.\dfrac{1}{2}+\left(\dfrac{1}{2}\right)^2=\left(x-\dfrac{1}{2}\right)^2\)

Answer 2

a,(4x+1)² e,\(\left(\dfrac{3}{2}x-\dfrac{2}{5}\right)^2\)

b,(x-\(\dfrac{1}{2}\))² g,\(\left(xy+1\right)^2\)

c,(\(x+\dfrac{3}{2}\))² h,\(\left(x+5\right)^2\)

d,\(\left(x-\dfrac{5}{4}\right)^2\) i,\(-\left(x-6\right)^2\)

k,\(-\left(2x+3\right)^2\)