\(2x^2-72=0\)
\(2x^2=72\)
\(\Rightarrow x^2=72:2=36\)
\(\Rightarrow\left\{{}\begin{matrix}x=6\\x=-6\end{matrix}\right.\)
Ta có: \(2x^2-72=0\)
\(\Rightarrow2x^2=72\)
\(\Rightarrow x^2=36\)
\(\Rightarrow x^2=6^2\)
\(\Rightarrow x=6\)
vậy \(x=6\)
\(2x^2-72=0\)
\(2x^2=72\)
\(x^2=36\)
\(x=\pm6\)
\(2x^2-72=0\)
\(\Leftrightarrow2x^2=72\)
\(\Leftrightarrow x^2=36\)
\(\Leftrightarrow x^2=6^2\)
\(\Leftrightarrow x=6\)