\(x^2-9x+18=0\)
\(\Delta=9^2-4.18=9>0\)
\(\Rightarrow\) Phương trình có hai nghiệm phân biệt:
\(x_1=6\)
\(x_2=3\)
\(x^2-9x+18=\left(x-3\right)\left(x-6\right)\)
Giải các phương trình sau:
a. \(\sqrt{25x+75}+2\sqrt{9x+27}=5\sqrt{x+3}+18\)
b. \(\sqrt{4x-8}-14\sqrt{\dfrac{x-2}{49}}=\sqrt{9x-18}+8\)
a)\(\sqrt{4x-12}+\sqrt{9x-27}-4\sqrt{x-3}+3-x\)
b) \(\sqrt{25x-25}-3\sqrt{x-2}=2+4\sqrt{x+3}+\sqrt{9x-18}\)
c) \(\sqrt{49x-98}-14\sqrt{\dfrac{x-2}{49}}=\sqrt{9x-18}+18\)
d) \(\sqrt{x+\sqrt{2x-1}}+\sqrt{x-\sqrt{2x-1}}=\sqrt{2}\)
giúp mk vs
Giải các phương trình sau:
a. \(\sqrt{25x+75}+3\sqrt{x-2}=2\sqrt{x-2}+\sqrt{9x-18}\)
b. \(\sqrt{\left(2x-1\right)^2}=4\)
c. \(\sqrt{\left(2x+1\right)^2}=3x-5\)
d. \(\sqrt{4x-12}-14\sqrt{\dfrac{x-2}{49}}=\sqrt{9x-18}+8\)
-4/5 căn 50-25x - 2/3 căn 18-9x +6=0
Tìm x:
\(\sqrt{9x+18}-0,5\sqrt{4x+8}-\dfrac{4}{5}\sqrt{25x+50}=-10\)
\(\sqrt{49x-98}-14\sqrt{\dfrac{x-2}{49}}=\sqrt{9x-18}+8\)
\(\sqrt{x-2}+\sqrt{4x-8}-\frac{1}{3}\sqrt{9x-18=12}\)
Bài 1: Tìm x, biết
a)\(2\sqrt{9x-27}-\dfrac{1}{5}\sqrt{25x-75}-\dfrac{1}{7}\sqrt{49x-147}=20\)
b) \(\sqrt{9x+18}-5\sqrt{x+2}+\dfrac{4}{5}\sqrt{25x+50}=6\)
c)\(\sqrt{16x-16}-\sqrt{9x-9}+\sqrt{4x-4}+\sqrt{x-1}=8\)
d) \(\sqrt{x+2\sqrt{x-1}}-\sqrt{x-2\sqrt{x-1}}=2\)
