Question

Can 7- căn 2>1

Answer 1

Ta có : \(\left\{{}\begin{matrix}\sqrt{7}>\sqrt{4}\\\sqrt{2}>\sqrt{1}\end{matrix}\right.\Rightarrow\sqrt{7}-\sqrt{2}>\sqrt{4}-\sqrt{1}=1\)

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Answer 2

\(Ta\text{ }có:\left(\sqrt{7}-\sqrt{2}\right)^2\\ =7-2\sqrt{14}+2\\ =9-\sqrt{56}>9-\sqrt{64}=9-8=1\\ \sqrt{7}-\sqrt{2}>1\)

Answer 3

1