De mak ban
\(Cosa=\sqrt{1-Sin^2a}=.......\)
\(tga=\dfrac{sina}{cosa}=.....\)
\(cotg=\dfrac{cosa}{sina}=......\)
ta có : \(sin^2a+cos^2a=1\Leftrightarrow cos^2a=1-sin^2a=1-\left(\dfrac{7}{25}\right)^2=\dfrac{576}{625}\)
\(\Rightarrow cosa=\pm\dfrac{24}{25}\)
ta có : \(tana=\dfrac{sina}{cosa}=\dfrac{\dfrac{7}{25}}{\pm\dfrac{24}{25}}=\pm\dfrac{7}{24}\)
\(cota=\dfrac{1}{tana}=\pm\dfrac{24}{7}\)
vậy \(cosa=\pm\dfrac{24}{25};tana=\pm\dfrac{7}{24};cota=\pm\dfrac{24}{7}\)