nhh = \(\dfrac{3,36}{22,4}=0,15\left(mol\right)\)
nCaSO3 = \(\dfrac{12}{120}=0,1\left(mol\right)\)
Pt: SO2 + Ca(OH)2 --> CaSO3 + H2O
....0,1 mol<---------------0,1 mol
mSO2 = 0,1 . 64 = 6,4 (g)
mN2 = (0,15 - 0,1) . 28 = 1,4 (g)
mhh = 6,4 + 1,4 = 7,8 (g)
% mSO2 = \(\dfrac{6,4}{7,8}.100\%=82,05\%\)
% mN2 = 100% - 82,05% = 17,95%
nCaSO3 = 12/120=0,1(mol)
nhh = 3,36/22,4=0,15(mol)
Pt: Ca(OH)2 +SO2-> CaSO3 + H2O
__________0,1 mol__0,1 mol
mSO2 = 0,1 . 64 = 6,4 (g)
mN2 = (0,15 - 0,1) . 28 = 1,4 (g)
mhh = 6,4 + 1,4 = 7,8 (g)
%mSO2 = 6,4/7,8.100%=82,05%
% mN2 = 100% - 82,05% = 17,95%