\(\left(5x+5\right)\left(2x-1\right)>0\)
\(\Leftrightarrow5\left(x+1\right)\left(2x-1\right)>0\)
Ta có bảng xét dấu:
x |
-1 1/2 |
x+1 | - 0 + // + |
2x-1 | - // - 0 + |
(x+1)(2x-1) | + 0 - 0 + |
5(x+1)(2x-1) | + 0 - 0 + |
Do đó: \(5\left(x+1\right)\left(2x-1\right)>0\)
\(\Leftrightarrow x< 1;x>\dfrac{1}{2}\)