Question

a^2 + 2ab + b^2 - ac - bc

Answer 1

\(a^2+2ab+b^2-ac-bc=\left(a+b\right)^2-c\left(a+b\right)=\left(a+b\right)\left(a+b-c\right)\)

Answer 2

Giải:

\(a^2+2ab+b^2-ac-bc=\left(a+b\right)^2-c\left(a+b\right)=\left(a+b\right)\left(a+b-c\right)\)

Answer 3

\(a^2+2ab+b^2-ac-bc=\left(a+b\right)^2-c\times\left(a+b\right)=\left(a+b\right)\times\left(a+b-c\right)\)

Answer 4

a² + 2ab + b² - ac - bc

= ( a² + 2ab + b² ) - ac - bc

= (a + b ) ² - c ( a + b )

= ( a+ b ) ( a + b - c )

Answer 5

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