Các câu hỏi tương tự
So sánh
\(a,2^{30}+3^{30}+4^{30}v\text{à}3^{20}+6^{20}+8^{20}\)
\(b,2^{30}+3^{30}+4^{30}v\text{à}3.24^{10}\)
\(c,2^0+2^1+2^2+...+2^{50}v\text{à}2^{51}\)
\(\frac{a}{1}=\frac{b}{4};\frac{b}{c}=\frac{3}{4}v\text{à }4a+b-c=8\)
So sánh :
\(a,2^{30}v\text{à}3^{20}\)
\(b,5^{300}v\text{à}3^{500}\)
\(c,2^{24}v\text{à}3^{16}\)
\(d,\left(0,3\right)^{40}v\text{à}\left(0,1\right)^{20}\)
So sánh:
a)\(2^{24}v\text{à}3^{16}\)
b)\(2^{300}v\text{à}3^{200}\)
c)\(71^5v\text{à}7^{20}\)
Cho: \(\frac{a-1}{2}=\frac{b+3}{4}=\frac{c-5}{6}v\text{à}:5a-3b-4c=46\)
Xác định a,b,c
a)\(\frac{z}{5}=\frac{x}{2}=\frac{y}{3}v\text{à}x.y-z=810\)
b)\(5x=3yv\text{à}2x^2-y^2=-28\)
c)\(\frac{x}{2}=\frac{y}{4}=\frac{z}{6}v\text{à}x^2+y^2+z^2=14\)
d)\(x:y:z=3:4:5v\text{à}5z^2-2y^2=594\)
So sánh các số hữu tỉ:
a) \(\frac{-17}{24}v\text{à}\frac{-25}{31}\)
b) \(\frac{-27}{38}v\text{à}\frac{-125}{195}\)
c) \(\frac{-22}{111}v\text{à}\frac{-27}{134}\)
So sánh các số hữu tỉ:
a) \(\frac{-17}{24}v\text{à}\frac{-25}{31}\)
b) \(\frac{-27}{38}v\text{à}\frac{-125}{195}\)
c) \(\frac{-22}{111}v\text{à}\frac{-27}{134}\)
* Giải chi tiết giúp mình !
So sánh các số sau:
a) \(0,5\sqrt{100}-\sqrt{\frac{4}{25}}v\text{à}\left(\sqrt{1\frac{1}{9}}-\sqrt{\frac{9}{16}}\right):5\)
b) \(\sqrt{25+9}v\text{à}\sqrt{25}+\sqrt{9}\)
Bài 1dựa vào tính chất bắc cầu của thứ tự
a,\(\frac{-24}{25}v\text{à}\frac{-23}{27}\)
b,\(\frac{22}{-67}v\text{à}\frac{51}{-152}\)
c,\(\frac{-33}{131}v\text{à}\frac{53}{-217}\)