Các câu hỏi tương tự
1) (4-3x) (10x-5)02) (7-2x) (4+8x) 03) (9-7x) (11-3x) 04) (7-14x) (x-2) 05) (2x+1) (x-3) 06) (8-3x) (-3x+5) 07) (16-8x) (2-6x) 08) (x+4) (6x-12) 09) (11-33x) (x+11) 010) (x-1/4) (x+5/6) 011) (7/8-2x) (3x+1/3) 012) 3x - 2x^2 013) 5x + 10x^2 014) 4x + 3x^2 015) -8x^2 + x 016) 10x^2 - 15x 017) x^2 -4 018) 9 - x^2 019) x^2 -1 020) (x-3) (2x-1) (2x-1) ( 2x+3)21) (5+4x) (-x+2) (5+4x) (7+5x)22) (4+x) (x-5) (3x-8) (x-5) 0 23) (3x-8) (7-21x) - (9+2x) (7-21x)24) (10+ 7x) (x+1) (9x-2)(...
Đọc tiếp
1) (4-3x) (10x-5)=0
2) (7-2x) (4+8x) = 0
3) (9-7x) (11-3x) = 0
4) (7-14x) (x-2) = 0
5) (2x+1) (x-3) = 0
6) (8-3x) (-3x+5) = 0
7) (16-8x) (2-6x) = 0
8) (x+4) (6x-12) = 0
9) (11-33x) (x+11) = 0
10) (x-1/4) (x+5/6) = 0
11) (7/8-2x) (3x+1/3) = 0
12) 3x - 2x^2 = 0
13) 5x + 10x^2 = 0
14) 4x + 3x^2 = 0
15) -8x^2 + x =0
16) 10x^2 - 15x = 0
17) x^2 -4 =0
18) 9 - x^2 = 0
19) x^2 -1 = 0
20) (x-3) (2x-1) = (2x-1) ( 2x+3)
21) (5+4x) (-x+2) = (5+4x) (7+5x)
22) (4+x) (x-5) = (3x-8) (x-5) = 0
23) (3x-8) (7-21x) - (9+2x) (7-21x)
24) (10+ 7x) (x+1) = (9x-2)(x-1)
25) (9x-4) (x-1/2) - (x-1/2) (6+x) = 0
26) 9x^2 - 1 = (3x-1) (x+4)
27) (x+7) (3x+1) = 49-x^2
28) (2x+1)^2 = (x-1)^2
29)x^3- 5x^2+6x = 0
30) 3x^2 + 5x + 2 = 0
Giảii giúpp mìnhh đyy mọii ngườii .
Help mk vs
a) (4x+1)(12x-1)(3x-2)(x+1)=4
b) (3x+4)(x+1)(6x+7)^2=6
c) (x-1)(x-2)(x-4)(x-18)=4x^2
Xem chi tiết
1) Rút gọn
x2 + 4x +4 \ 3x + 6 ; 12x + 3x \ 2x(x + 4)
2) Quy đồng mẫu
a/ 6 \ x2 + 4x ; 3 \ 2x + 8
b/ 1 \ x + 2 ; 1 \ (x + 2)(4x +7)
c/ y - 12 \ 6y - 36 ; 6 \ y2 - 6y
d/ 1 \ x + 3 ; 1 \ (x + 3)(x + 2) ; 1 \ (x + 2)(4x + 7)
1. TÌm x:
a)4x^2-2x+3-4x.(x-5)=7x-3
b)-3x.(x-5)+5.(x-1)+3x^2=4x
c)7x.(x-2)-5.(x-1)=21x^2-14x^2+3
d)3.(5x-1)-x.(x-2)+x^2-13x=7
e) 1/5x.(10x-15)-2x.(x-5)=12
1. TÌm x:
a)4x^2-2x+3-4x.(x-5)=7x-3
b)-3x.(x-5)+5.(x-1)+3x^2=4x
c)7x.(x-2)-5.(x-1)=21x^2-14x^2+3
d)3.(5x-1)-x.(x-2)+x^2-13x=7
e) 1/5x.(10x-15)-2x.(x-5)=12
Phân tích thành nhân tử
1, a^4+a^2+1
2,a^4+4b^4
3,64x^4+1
4, x^5+x^4+1
5, x^7+x^2+1
6, x^8+x+1
7, x^4-4x^2+4x-1
8, a^16+a^8b^8+b^16
tìm x biết
a) (6x-3) (2x+4) + (4x-1) (5-3x) = -21
b) 6x (3x+5) - 2x (9x-2) + (17-x) (x-1) + x (x-18) =0
c) (15-2x) (4x+1) - (13-4x) (2x-3) - (x-1) (x+2) + x2=52
d) (8x-3) (3x+2) - (4x+7) (x+4) = (2x+1) (5x-1) - 33
Tìm x:
a) 4(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
b) 5(3x + 5) - 4(2x - 3) = 5x + 3(2x + 12) + 1
c) 2(5x - 8) - 3(4x - 5) = 4(3x - 4) +11
d) 5x - 3{4x - 2[4x - 3(5x - 2)]} = 182
(Bài 14; Tìm x biết
1) x ^ 2 - 9 = 0
4) 4x ^ 2 - 4 = 0
7) (3x + I) ^ 2 - 16 = 0
10) (x + 3) ^ 2 - x ^ 2 = 45
2) 25 - x ^ 2 = 0
5) 4x ^ 2 - 36 = 0
8) (2x - 3) ^ 2 - 49 = 0
11) (5x - 4) ^ 2 - 49x ^ 2 = 0
3) - x ^ 2 + 36 = 0
6) 4x ^ 2 - 36 = 0
9) (2x - 5) ^ 2 - x ^ 2 = 0
12) 16 * (x - 1) ^ 2 - 25 = 0
Phân tích thành nhân tử ( thêm bớt hạng tử)
1, a^4+a^2+1
2,a^4+4b^4
3,64x^4+1
4, x^5+x^4+1
5, x^7+x^2+1
6, x^8+x+1
7, x^4-4x^2+4x-1
8, a^16+a^8b^8+b^16