Tính\(\frac{4x^2-16}{1-2x+x^2}:\frac{3x+6}{1-x}\)
\( {4x^2-16{} \over 1-2x+x^2}\):\( {3x +6{} \over 1-x}\)
=
xin loi nhé
=\( {(2x-4) (2x+4){} \over (1-x)^2}\):\( {3. {(x+2)} \over 1-x}\)
=\( {4{(x-2)(x+2)} \over (1-x)^2}\).\({1-x \over 3(x+2)}\)
=\({4{(x-2)} \over 3(1-x)}\)