Ta có: \(3^{x+2}+3^x=10\)
\(\Rightarrow3^x\cdot3^2+3^x=10\)
\(\Rightarrow3^x\cdot\left(3^2+1\right)=10\)
\(\Rightarrow3^x\cdot\left(9+1\right)=10\)
\(\Rightarrow3^x\cdot10=10\)
\(\Rightarrow3^x=\frac{10}{10}\)
\(\Rightarrow3^x=1\)
\(\Rightarrow x=0\)
Vậy: \(x=0\)