\(\left(3x+1\right)^2-4\cdot\left(x-3\right)^2=0\)
\(\left(3x+1\right)^2-\left(2x-6\right)^2=0\)
\(\left(3x+1-2x+6\right)\left(3x+1+2x-6\right)=0\)
\(\left(x+7\right)\left(5x-5\right)=0\)
\(\left[{}\begin{matrix}x+7=0\\5x-5=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-7\\x=1\end{matrix}\right.\)
Bài 1: Tìm x biết a) x^3 - 4x^2 - x + 4= 0 b) x^3 - 3x^2 + 3x + 1=0 c) x^3 + 3x^2 - 4x - 12=0 d) (x-2)^2 - 4x +8 =0
Giải các phương trình sau
1. ( x-6) ( x+7) - 5 ( 6-x) ( 3x-1)=0
2. ( 3x+1)^2 - ( 2x-5)^3=0
3. ( 4x+3)^2 -4 (x-1)^2=0
4. (x+5)^2 (3x+2)^2 =x^2(x+5)^2
5. x(x+3)^2 - 4x=0
Bài 1: Tìm x
a) (x+2)(x2-2x+4)+(x+2)2=0
b) 9x2-4-(3x-2)2=0
Bài 1, tìm x
a, x2+\(\frac{1}{4}\)=x
b, x2-4x=-4
c, x3+12x2+36x=0
d, (3x-1)2=(x-3)2
e, x3+3x2+3x+1=0
f, x3+1=0
tìm x, biết:
a) (3x-1)2+(x+3)3-5(2x-3)(x+3)=0
b) x2-4x+4-(x+3)(x-3)=0
c) x2-3x+2=0
Tìm x
a)4(x+3)(3x-2)-3(x+1)(4x-1)=-27
b)(x+1)(3x²-x+1)+x²(4-3x)=5/2
c)2(x-2)(x+2)+4(x-2)(x+1)+(x+2)(8+5x)=0
d)(2x+1)(5x-1)=20x²-16x-1
😭😭😭😭😭
Bài 1 rút gọn
a) (x+3)(x-3)-(x-3)2
b) (2x+1)2+2(2x+1)(x-1)+(x-1)2
c) x(x-3)(x+3)-(x^2 +1)(x^2-1)
Bài 2 tìm x
a) (x+2)2-x^2-3x=21
b) x^2+x-12=0
c) x^3-3x^2+3x-126=0
d) x^3-5x^2+8x-4=0
e) 2x^3-x^2+3x+6=0
f) (x^2+x) (x^2+x+1)=6
Tìm x:
a)x(2x-4)-(x-2)(2x+3)
b)x(3x+2)+(x+1)^2-(2x-5)(2x+5)=-12
c)(x-1)(x^2+x+1)-x(x-3)^2=6x^2
d)x^2-x=0
e)(x+2)(x-3)-x-2=0
f)3x^3-27x
Giup mik vs nha
