Ta có: \(\frac{x}{8}=\frac{9}{4}\)
\(\Leftrightarrow x=\frac{9\cdot8}{4}=\frac{72}{4}=18\)
Vậy: x=18
Ta có: \(\frac{x}{8}=\frac{9}{4}\)
\(\Leftrightarrow x=\frac{9\cdot8}{4}=\frac{72}{4}=18\)
Vậy: x=18
a, (x-3)^x+8=4*(x-2)^x+6
b, (x-3)^x+10=9*(x-3)^x+8
tìm x
9 phần 4 tất cả mũ x-6 = 27 phần 8 tất cả mũ x-2
tìm x
\(\left(\dfrac{9}{4}\right)^{x+6}^{^{ }^{ }^{ }}=\left(\dfrac{27}{8}\right)^{x-2}\)
a) 3^2x-1=243
b) 3^x+1=9^x
c) (4/7-1/2x)^3=-8/34
Bài 1:Tính
1) (1/2)^3 (3/2)^2
2) (2/3)^3 (3/2)^5
3) (5/4)^5 (4/5)^7
4) (-5/6)^6 (6/5)^8
5)(-4/3)^3 (9/16)^5
6) (1/3)^4 (-9/2)^6
7)(-4/9)^3 (-27/20)^4
8) (0,2)^4 . 5^6
9) (-4/3)^3 (9/16)^5
10) (-0,2)^3 .(-5)^5
11) (-4)^4 .(0,25)^6
12) $^2 . (0,2)^3
13) (0,5)^2 . 2^4
14) (-0,5)^3 .2^6
15) (-0,5)^5 .(-2)^10
16) (0,125)^2 .8^4
17) (0,125)^5 . (-8)^4
18) (-0,125)^7 . 8^10
19) (-0,1)^4 . 10^7
20) (0,1)^5 . (-10)^10
Giúp mình với ạ,mình cảm ơn ạ
1,\(\dfrac{3}{16}\)- ( x - \(\dfrac{5}{4}\) ) - ( \(\dfrac{3}{4}\) + \(\dfrac{-7}{8}\) - 1 ) = \(2\dfrac{1}{2}\)
2,\(\dfrac{1}{2}\) . ( \(\dfrac{1}{6}\) - \(\dfrac{9}{10}\) ) = \(\dfrac{1}{5}\) - x + ( \(\dfrac{1}{15}\) - \(\dfrac{-1}{5}\) )
Giúp mik nhanh với ạ
\(\left(\dfrac{1}{2}\right)^3.\left[\left(\dfrac{1}{2}\right)^X\right]^X-\dfrac{5}{8}=\left(\dfrac{1}{2}\right)^4.\left(-9\right)\)
TÌM THƯƠNG A/B
A= 9/1 + 8/2 + 7/3 + 6/4 + 5/5 + 4/6 + 3/7 + 2/8 + 1/9
B=1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + 1/8 + 1/9 + 1/10
HELP ME
tìm tập hợp các số nguyên x biết
a) \(\dfrac{1}{2}-\left(\dfrac{1}{3}+\dfrac{1}{4}\right)< x< \dfrac{1}{48}-\left(\dfrac{1}{16}-\dfrac{1}{6}\right)\)
b) \(\dfrac{1}{4}+\dfrac{8}{9}\le\dfrac{x}{36}< 1-\left(\dfrac{3}{8}-\dfrac{5}{6}\right)\)