\(\left(x+2\right)^2-x+4=0\)
\(\Leftrightarrow x^2+4x+4-x+4=0\)
\(\Leftrightarrow x^2+3x+8=0\)
\(\Leftrightarrow\left(x+\frac{3}{2}\right)^2+\frac{23}{4}=0\)
\(\Leftrightarrow\left(x+\frac{3}{2}\right)^2=-\frac{23}{4}\) (vô lí)
Vậy...
tìm x, y biết
a, \(5x^2+5y^2+8xy+2x-2y+2=0\)
b, \(\left(x-2\right)\left(x-3\right)\left(x-4\right)\left(x-5\right)+1=0\)
Tìm x, biết:
a) \(\left(x-3\right)\left(x^2+3x+9\right)+x\left(x+2\right)\left(2-x\right)=1\)
b) \(\left(x-3\right)^3-\left(x-3\right)\left(x^2+3x+9\right)+6\left(x+1\right)^2+3x^2=15\)
c)\(\left(x-1\right)^3-\left(x+3\right)\left(x^2-3x+9\right)+3\left(x^2-4\right)=2\)
d) \(\left(x-2\right)^3+6\left(x+1\right)^2-x^3+12=0\)
tìm x biét
a, \(\left(x+2\right)^2-9=0\)
b, \(\left(x+2\right)^2-x^2+4=0\)
c, \(\left(x-3\right)^2=\left(2-3x\right)^2\)
d, \(x^3-6x^2+12x-8=0\)
e. \(\left(x +1\right)^3+\left(x-2\right)^3=0\)
Tìm x biết :
a)\(\left(2x+5\right)^3-\left(x+2\right)^3-\left(x+3\right)^3=0\)
b)\(\left(x+7\right)^3-\left(2x+13\right)^3+\left(x+6\right)^3=0\)
tìm x biết
1) \(\left(x+2\right)-\left(x^2-2x+4\right)-x\left(x^2+2\right)=15\)
2) \(\left(x+3\right)^3-x\left(3x+1\right)^2+\left(2x+1\right)\left(4x^2-2x+1\right)=28\)
Mọi người yêu dấu ơi~Xin hãy giúp mình giải bài này với a~Mình sẽ tick~Like và Bình luận cho mina a~
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Tìm x
a,\(\left(x+2\right).\left(x^2-2x+4\right)-\left(x^2+x\right)=15\)
b,\(\left(x+3\right)^3-x.\left(3x+1\right)^2+\left(2x+1\right),\left(4x^2-2x+1\right)=28\)c,\(\left(x^2-1\right)^3-\left(x^4+2x+1\right).\left(x^2-1\right)=0\)
d,\(\left(x-1\right).\left(x^3+x+1\right)-x\left(x-2\right).\left(x+2\right)=5\)
e,\(\left(x-1\right)^3-\left(x+3\right).\left(x^2-3x+9\right)+3\left(x^2-4\right)=2\)
f,\(\left(x-3\right)^3-\left(4x+3\right)^2+\left(3x-1\right).\left(9x^2+3x+1\right)=4.\left(3x^3-7\right)\)
Cảm ơn các bạn nhiều lắm a~
Tìm x:
1, \(\left(x-5\right)\cdot\left(x+5\right)-\left(x+3\right)^2=2x-3\)
2,\(\left(2x+3\right)^2+\left(x-1\right)\cdot\left(x+1\right)=5\cdot\left(x+2\right)^2\)
3, \(\left(x-4\right)^3-\left(x-5\right)\cdot\left(x^2+5x+25\right)=\left(x+2\right)\cdot\left(x^2-2x+4\right)-\left(x+4\right)^3\)
Tìm x :
\(\left(x-4\right)^3-\left(x-5\right)\cdot\left(x^2+5x+25\right)=\left(x+2\right)\cdot\left(x^2-2x+4\right)-\left(x+4\right)^3\)
Tìm x bt :
a,\(\left(x+2\right)\left(x+3\right)-\left(x-2\right)\left(x+5\right)=0\)
b, \(3x\left(x-5\right)-\left(x-1\right)\left(2+3x\right)\)
