Có: cos\(\alpha=\sqrt{1-sin^2\alpha}\)=\(\sqrt{1-\left(\frac{3}{5}\right)^2}=\frac{4}{5}\)
tan\(\alpha=\frac{sin\alpha}{cos\alpha}=\frac{3.5}{5.4}=\frac{3}{4}\)
cot\(\alpha=\frac{1}{tan\alpha}\)\(=\frac{4}{3}\)
CMR
a)\(\frac{1+\cos\alpha}{\sin\alpha}=\frac{\sin\alpha}{1-\cos\alpha}\)
b)\(\frac{\tan\alpha+1}{\tan\alpha-1}=\frac{1+\cot\alpha}{1-\cot\alpha}\)
c) \(\tan^2\alpha-\sin^2\alpha=\tan^2\alpha.\sin^2\alpha\)
d)\(\frac{1-4\sin^2\alpha.\cos^2\alpha}{\left(\sin\alpha-\cos\alpha\right)^2}=\left(\sin\alpha+\cos\alpha\right)^2\)
cho \(\tan\alpha=\frac{7}{24}.\) tinh \(\sin\alpha,\cos\alpha,\cot\alpha\)
a, Cho cos α = 0,8. Hãy tính: sin α, tan α, cot α ?
b, Hãy tìm sin α, cos α, biết tan α = \(\frac{1}{3}\)
CM các hệ thức sau:
a) \(1+\tan^2\alpha=\frac{1}{\cos^2\alpha}\)
b) \(1+\cot^2\alpha=\frac{1}{\sin^2\alpha}\)
c) \(\cot^2\alpha-\cos^2\alpha=\cot^2\alpha.\cos^2\alpha\)
d) \(\frac{1+\cos\alpha}{\sin\alpha}=\frac{\sin\alpha}{1-\cos\alpha}\)
Sử dụng định nghĩa các tỉ số lượng giác của 1 góc nhọnđể chứng minh rằng:với mỗi góc nhọn α tùy ý ,ta có:
a,tan α=\(\frac{sin\alpha}{cos\alpha}\),cot α=\(\frac{cos\alpha}{sin\alpha}\),tan α.cot α=1
b,sin2α+cos2α=1
c,1+tan2α=\(\frac{1}{cos^2\alpha}\),1+cot2α=\(\frac{1}{sin^2\alpha}\)
a) Biết \(\sin\alpha=\dfrac{9}{15}\). Tính \(\cos\alpha,\tan\alpha,\cot\alpha\)
b) Biết \(\cos\alpha=\dfrac{3}{5}\). Tính\(\sin\alpha,\tan\alpha,\cot\alpha\)
Bài 1: Tính:
a) \(A=4\cos^2\alpha-6\sin^2\alpha\) biết \(\sin\alpha=\frac{1}{5}\)
b) \(B=\sin\alpha.\cos\alpha\) biết \(\tan\alpha+\cot\alpha=3\)
c) \(C=\cot^2\alpha-\cos^2\alpha.\cot^2\alpha\) biết \(\sin\alpha=\frac{3}{4}\)
Chứng minh:
a)\(cot^2\alpha-cos^2\alpha\cdot cot^2\alpha=cos^2\alpha\)
b)\(tan^2\alpha-sin^2\alpha\cdot tan^2\alpha=sin^2\alpha\)
c) \(\dfrac{1-cos^2}{sin\alpha}\) = \(\dfrac{sin\alpha}{1+cos\alpha}\)
d)\(tan^2\alpha-sin^2\alpha=tan^2\cdot sin^2\alpha\)
e) \(\sin^6\alpha+cos^6\alpha+3sin^2\cdot cos^2\alpha=1\)
Cho \(\tan\alpha=\frac{3}{5}\), hãy tính giá trị của:
a) \(M=\frac{\sin\alpha+\cos\alpha}{\sin\alpha-\cos\alpha}\)
b) \(N=\frac{\sin\alpha\cos\alpha}{\sin^2\alpha-\cos^2\alpha}\)
c) \(P=\frac{\sin^3\alpha+\cos^3\alpha}{2\sin\alpha\cos^2\alpha+\cos\alpha\sin^2\alpha}\)
