Question

_{0,2 mol Ca0 vào 120 g H20 . Sau đó thêm tiếp 6,2g Na2O. Xác định C% ddnđ khi hòa tan}

Answer 1

PTHH: \(CaO+H_2O\rightarrow Ca\left(OH\right)_2\)

_______0,2------------------->0,2___________(mol)

\(n_{Na_2O}=\frac{6,2}{62}=0,1\left(mol\right)\)

PTHH: \(Na_2O+H_2O\rightarrow2NaOH\)

________0,1------------------>0,2_______(mol)

=> \(\left\{{}\begin{matrix}C\%_{Ca\left(OH\right)_2}=\frac{0,2.74}{0,2.56+120+6,2}.100\%=10,77\%\\C\%_{NaOH}=\frac{0,2.40}{0,2.56+120+6,2}.100\%=5,82\%\end{matrix}\right.\)