Question

1. Tìm x :

a. 37-(x-25)=x+14
b. 3x-(6³-x)=2005

Answer 1

a, \(37-\left(x-25\right)=x+14\\ 37-x+25=x+14\\ 62-x=x+14\\ x+x=62-14\\ 2x=48\\ x=24\)

vậy \(x=24\)

b, \(3x-\left(6^3-x\right)=2005\\ 3x-\left(216-x\right)=2005\\ 3x-216+x=2005\\ 3x+x=2005+216\\ 4x=2221\\ x=\frac{2221}{4}\)

vậy \(x=\frac{2221}{4}\)

Answer 2

b, \(3x-\left(6^3-x\right)=2005\)

=> \(3x-6^3+x=2005\)

=> \(4x=2005+6^3\)

=> \(4x=2221\)

=> \(x=\frac{2221}{4}\) (t/mãn)

Chúc bạn học tốt!!