Question

3-(6/7)^0 + (1/2)^2:2

Answer 1

Ta có: \(3-\left(\frac{6}{7}\right)^0+\left(\frac{1}{2}\right)^2:2\)

\(=3-1+\frac{1}{4}\cdot\frac{1}{2}\)

\(=2+\frac{1}{8}\)

\(=\frac{17}{8}\)

Answer 2

\(3-\left(\frac{6}{7}\right)^0+\left(\frac{1}{2}\right)^2:2\)

=\(3-1+\frac{1}{4}.\frac{1}{2}=2+\frac{1}{8}=\frac{17}{8}\)