\(m_{ddH_2SO_4}=10\left(t\right)=10000000\left(g\right)\)
\(\Rightarrow m_{H_2SO_4}=\frac{10000000.98\%}{100\%}=9800000\left(g\right)\)
\(\Rightarrow n_{H_2SO_4}=\frac{9800000}{98}=100000\left(mol\right)\)
\(PT:Ca_3\left(PO_4\right)_2+2H_2SO_4\rightarrow Ca\left(HPO_4\right)_2+2CaSO_4\)
100000 50000 100000 (mol)
\(m_{Ca\left(HPO_4\right)_2}=50000.232=11600000\left(g\right)=11,6\left(t\right)\)
\(m_{CaSO_4}=100000.136=13600000\left(g\right)=13,6\left(t\right)\)
\(\Rightarrow m_{superphotphatđơn}=11,6+13,6=25,2\left(t\right)\)
\(\Rightarrow H_{pư}=\frac{20,3}{25,2}.100\%=80,56\%\)