Question

Phân tích thành nhân tử
a, \(x+2\sqrt{x}\)

b, \(3x-2\sqrt{x}\)

c, \(2\sqrt{x}-4x\)

d, \(4x-3\sqrt{x}\)

Answer 1

a, Ta có : \(x+2\sqrt{x}\)\(=\sqrt{x}\left(\sqrt{x}+2\right)\)

b, Ta có : \(3x-2\sqrt{x}=\sqrt{x}\left(3\sqrt{x}-2\right)\)

c, Ta có : \(2\sqrt{x}-4x=2\sqrt{x}\left(1-2\sqrt{x}\right)\)

d, Ta có : \(4x-3\sqrt{x}=\sqrt{x}\left(4\sqrt{x}-3\right)\)

Answer 2

a/\(x+2\sqrt{x}=\sqrt{x}\left(\sqrt{x}+2\right)\)

b/\(3x-2\sqrt{x}=\sqrt{x}\left(3\sqrt{x}-2\right)\)

c/\(2\sqrt{x}-4x=2\sqrt{x}\left(1-2\sqrt{x}\right)\)

d/\(4x-3\sqrt{x}=\sqrt{x}\left(4\sqrt{x}-3\right)\)

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