Question

Bài 1:Tính

\(\left(\sqrt{18}+\sqrt{32}-\sqrt{50}\right)\cdot\sqrt{2}\)

Answer 1

Bài 1: Tính

Ta có: \(\left(\sqrt{18}+\sqrt{32}-\sqrt{50}\right)\cdot\sqrt{2}\)

\(=\sqrt{36}+\sqrt{64}-\sqrt{100}\)

\(=6+8-10=14-10=4\)

Answer 2

\(\left(\sqrt{18}+\sqrt{32}-\sqrt{50}\right).\sqrt{2}\)

\(=\sqrt{2}.\left(\sqrt{9}+\sqrt{16}-\sqrt{25}\right).\sqrt{2}\)

\(=2.\left(3+4-5\right)=2.2=4\)

Answer 3

Bài giải

\(\left(\sqrt{18}+\sqrt{32}-\sqrt{50}\right)\cdot\sqrt{2}\)

\(=\sqrt{36}+\sqrt{64}-\sqrt{100}\)

\(=6+8-10\)

\(=4\)