ĐKXĐ: \(\left\{{}\begin{matrix}x\ge0\\x\ne\frac{9}{49}\end{matrix}\right.\)
\(\frac{3\sqrt{x}-6}{7\sqrt{x}-3}=\frac{1}{6}\Leftrightarrow6\left(3\sqrt{x}-6\right)=7\sqrt{x}-3\)
\(\Leftrightarrow18\sqrt{x}-36=7\sqrt{x}-3\)
\(\Leftrightarrow11\sqrt{x}=33\)
\(\Rightarrow\sqrt{x}=3\Rightarrow x=9\) (thỏa mãn)