\(=\frac{1}{\sqrt{2}}.\sqrt{8+2\sqrt{7}}=\frac{1}{\sqrt{2}}\sqrt{\left(\sqrt{7}+1\right)^2}=\frac{\sqrt{7}+1}{\sqrt{2}}\)
\(=\frac{1}{\sqrt{2}}.\sqrt{8+2\sqrt{7}}=\frac{1}{\sqrt{2}}\sqrt{\left(\sqrt{7}+1\right)^2}=\frac{\sqrt{7}+1}{\sqrt{2}}\)
Tính:
\(a)\sqrt{4-2\sqrt{3}}+\sqrt{7-4\sqrt{3}}\\ b)\frac{6}{\sqrt{7}+2}+\sqrt{\frac{2}{8+3\sqrt{7}}}\)
Giai phương trình : \(\frac{4}{\sqrt{7}-\sqrt{3}}+\frac{6}{3+\sqrt{3}}+\frac{\sqrt{7}-7}{\sqrt{7}-1}\)
Rút gọn: \(\frac{\sqrt{2}}{2}.\sqrt{7+5.\sqrt[4]{5}+3.\sqrt[4]{25}+\sqrt[4]{125}}\)
giải phương trình:
a, \(\sqrt{x+6-4\sqrt{x+2}}+\sqrt{x+11-6\sqrt{x+2}}=1\)
b, \(\sqrt{x+2-4\sqrt{x-2}}+\sqrt{x+7-6\sqrt{x-2}}=1\)
c, \(\sqrt{x-7}+\sqrt{9-x}=x^2-16x+66\)
Cho hàm số f(x) = \(\left(x^4+\sqrt{2}x-7\right)^{2018}\). Tính f(a) với a = \(\left(4+\sqrt{15}\right)\left(\sqrt{5}-3\right)\sqrt{4-\sqrt{15}}\)
Cho \(A=\left(\frac{x-\sqrt{x}+7}{x-4}+\frac{1}{\sqrt{x}-2}\right):\left(\frac{\sqrt{x}+2}{\sqrt{x}-2}-\frac{\sqrt{x}-2}{\sqrt{x}+2}-\frac{2\sqrt{x}}{x-4}\right)\)
a) ĐKXĐ , Rút Gọn
b)So sánh A với 1/A
Tính: \((\sqrt{\sqrt{7+\sqrt{48}}}-\sqrt{\sqrt{28-16\sqrt{3}}})\sqrt{\sqrt{7+\sqrt{48}}}\)
Rút gọn các biểu thức : a) \(\sqrt{\left(3+\sqrt{5}\right)^2}\)
b) \(\sqrt{\left(5-\sqrt{5}\right)^2}\)
c) \(\sqrt{\left(4-\sqrt{11}\right)^2}+\sqrt{11}\)
d) \(\sqrt{\left(\sqrt{8}-7\right)^2}-\sqrt{8}\)
cho \(x\ge-\dfrac{1}{3}\). tìm GTNN của \(E=5x-6\sqrt{2x+7}-4\sqrt{3x-1}+2\)