\(\dfrac{5}{17}+\dfrac{2}{3}-\dfrac{20}{12}+\dfrac{7}{9}+\dfrac{12}{17}=\)
\(\dfrac{5}{17}+\dfrac{2}{3}-\dfrac{20}{12}+\dfrac{7}{9}+\dfrac{12}{17}=\)
\(\dfrac{5}{17}+\dfrac{2}{3}-\dfrac{20}{12}+\dfrac{7}{9}+\dfrac{12}{17}=\dfrac{7}{9}\)
Ta có: \(\dfrac{5}{17}+\dfrac{2}{3}-\dfrac{20}{12}+\dfrac{7}{9}+\dfrac{12}{17}\)
\(=\left(\dfrac{5}{17}+\dfrac{12}{17}\right)+\left(\dfrac{2}{3}-\dfrac{5}{3}\right)+\dfrac{7}{9}\)
\(=1-1+\dfrac{7}{9}=\dfrac{7}{9}\)
1 phần 10 - (1 phần 3) mũ 2 : 5 phần 9
\(\dfrac{1}{10}-\left(\dfrac{1}{3}\right)^2:\dfrac{5}{9}\)
= \(\dfrac{1}{10}-\dfrac{1}{9}:\dfrac{5}{9}\)
= \(\dfrac{1}{10}-\dfrac{1}{9}.\dfrac{9}{5}\)
= \(\dfrac{1}{10}-\dfrac{1}{5}\)
= \(\dfrac{1}{10}-\dfrac{2}{10}\)
= \(-\dfrac{1}{10}\)
\(\dfrac{1}{10}-\left(\dfrac{1}{3}\right)^2:\dfrac{5}{9}\)
=\(\dfrac{1}{10}-\dfrac{1}{9}:\dfrac{5}{9}\)
=\(\dfrac{1}{10}-\dfrac{1}{9}.\dfrac{9}{5}\)
=\(\dfrac{1}{10}-\dfrac{1}{5}\)
=\(\dfrac{1}{10}-\dfrac{2}{10}\)
=\(\dfrac{-1}{10}\)=-0.1
Ta có: \(\dfrac{1}{10}-\left(\dfrac{1}{3}\right)^2:\dfrac{5}{9}\)
\(=\dfrac{1}{10}-\dfrac{1}{9}:\dfrac{5}{9}\)
\(=\dfrac{1}{10}-\dfrac{1}{9}\cdot\dfrac{9}{5}\)
\(=\dfrac{1}{10}-\dfrac{1}{5}\)
\(=\dfrac{1}{10}-\dfrac{2}{10}\)
\(=-\dfrac{1}{10}\)
Tìm x biết x2- 9*x=0
\(x^2-9x=0\\ \Rightarrow x\left(x-9\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\x-9=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=9\end{matrix}\right.\)
Vậy \(x\in\left\{0;9\right\}\)
x2− 9x=0
⇒x (x − 9) = 0
⇒[x = 0x − 9 = 0
⇒[ x = 0x = 9
Vậy x∈{0;9}
Bài 12 Tìm số nguyên x lớn nhất sao cho :
a, x<-170/17
b,x<-13/3
Bài 13 Tìm số nguyên x nhỏ nhất sao cho :
a,x>-12/13
b,x>-45/15
Mn giải nhanh giùm mk với ạ mk đang cần gấp
Thanks mn
Bài 12:
a. \(x< -\dfrac{170}{17}=-10\rightarrow\) x nguyên max = -11
b. \(x< -\dfrac{13}{3}=-4,\left(3\right)\rightarrow\)x nguyên max là -5
Bài 13:
a. \(x>-\dfrac{12}{13}=-0,926..\rightarrow\)x nguyên min = 0
b. \(x>-\dfrac{45}{15}=-3\rightarrow\)x nguyên min = -2
Bài 12 Tìm số nguyên x lớn nhất sao cho :
a, x<-170/17
b,x<-13/3
Bài 13 Tìm số nguyên x nhỏ nhất sao cho :
a,x>-12/13
b,x>-45/15
Mn giải nhanh giùm mk với ạ mk đang cần gấp
Thanks mn
B12
a) ta có \(\dfrac{170}{17}=10\Rightarrow x=9\)
b) ta có \(\dfrac{13}{3}=4,333...\Rightarrow x=4\)
B13
a) x>\(\dfrac{-12}{13}\Rightarrow x=-1\)
b) ta có: \(\dfrac{-45}{15}\Rightarrow x>-3\Rightarrow x=-2\)
Bài 9: Tìm x, y, z, t nguyên biết
12/-6=x/5=-y/3=z/-17=-t/-9
Bài 10: Tìm x, y, z, t, u biết:
4/3=12/9=8/x=y/21=40/2=16/t=u/111
Bài 11: Tìm x, y, z, t, u biết:
-7/6=x/18=-98/y=-14/z=t/102=u/-78
Mong mn giải nhanh giúp ạ.
Mk đang cần gấp để nộp cho thầy ạ
Bài 9:
Ta có: \(\dfrac{12}{-6}=\dfrac{x}{5}=\dfrac{-y}{3}=\dfrac{z}{-17}=\dfrac{-t}{-9}\)
\(\Leftrightarrow\dfrac{x}{5}=\dfrac{-y}{3}=\dfrac{-z}{17}=\dfrac{t}{9}=-2\)
\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{x}{5}=-2\\\dfrac{-y}{3}=-2\\\dfrac{-z}{17}=-2\\\dfrac{t}{9}=-2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-10\\-y=-6\\-z=-34\\t=-18\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-10\\y=6\\z=34\\t=-18\end{matrix}\right.\)
Vậy: (x,y,z,t)=(-10;6;34;-18)
Bài 11:
Ta có: \(\dfrac{-7}{6}=\dfrac{x}{18}=\dfrac{-98}{y}=\dfrac{-14}{z}=\dfrac{t}{102}=\dfrac{u}{-78}\)
\(\Leftrightarrow\dfrac{x}{18}=\dfrac{-98}{y}=\dfrac{-14}{z}=\dfrac{t}{102}=\dfrac{u}{-78}=\dfrac{-7}{6}\)
Ta có: \(\dfrac{x}{18}=\dfrac{-7}{6}\)
\(\Leftrightarrow x=\dfrac{18\cdot\left(-7\right)}{6}=-21\)
Ta có: \(\dfrac{-98}{y}=\dfrac{-7}{6}\)
\(\Leftrightarrow y=\dfrac{-98\cdot6}{-7}=84\)
Ta có: \(\dfrac{-14}{z}=\dfrac{-7}{6}\)
\(\Leftrightarrow z=\dfrac{-14\cdot6}{-7}=12\)
Ta có: \(\dfrac{u}{-78}=\dfrac{-7}{6}\)
\(\Leftrightarrow u=\dfrac{-78\cdot\left(-7\right)}{6}=\dfrac{78\cdot7}{6}=91\)
Ta có: \(\dfrac{t}{102}=\dfrac{-7}{6}\)
\(\Leftrightarrow t=\dfrac{-7\cdot102}{6}=-7\cdot17=-119\)
Vậy: (x,y,z,t,u)=(-21;84;12;-119;91)
Nguyễn Lê Phước Thịnh giải giùm mk bài 10 đc ko ạ
Bài 1 tìm số nguyên x,y biết
a, x/3=y/7
b,x/y-1=5/-19
\(\dfrac{x}{3}=\dfrac{y}{7}\Rightarrow\dfrac{x}{y}=\dfrac{3}{7}\)
\(\dfrac{x}{y}-1=\dfrac{-5}{19}\Rightarrow\dfrac{x}{y}=\dfrac{14}{19}\)
Vô lí => không có x,y thỏa mãn
a) Ta có: \(\dfrac{x}{3}=\dfrac{y}{7}\)
nên \(\dfrac{x}{y}=\dfrac{3}{7}\)
b) Ta có: \(\dfrac{x}{y-1}=\dfrac{5}{-19}\)
\(\Leftrightarrow\dfrac{x}{5}=\dfrac{y-1}{-19}\)
hay \(\dfrac{x}{5}=\dfrac{1-y}{19}\)
Tìm x, biết:
-28/4 nhỏ hơn hoặc bằng x nhỏ hơn -21/7
\(a,ĐKXĐ:n-1\ne0\Leftrightarrow x\ne1\)
b, \(n=0\Rightarrow A=\dfrac{3}{0-1}=-3\)
\(n=5\Rightarrow A=\dfrac{3}{5-1}=\dfrac{3}{4}\)
\(n=-2\Rightarrow A=\dfrac{3}{-2-1}=-1\)
tìm x,y,z
a) \(\frac{-6}{12}=\frac{x}{8}=\frac{-7}{y}=\frac{z}{-18}\)
b)\(-\frac{-10}{y}=\frac{x}{-9}=-1\frac{2}{3}=\frac{-z}{12}\)
a, \(\frac{-6}{12}=\frac{x}{8}=\frac{-7}{y}=\frac{z}{-18}\)
\(\Rightarrow\) \(\frac{-1}{2}=\frac{x}{8}=\frac{-7}{y}=\frac{z}{-18}\)
\(\Rightarrow\) x = (-1) . 8 : 2 = -4 ; y = 2 . (-7) : (-1) = 14 ; z = (-1)(-18) : 2 = 9
Vậy x = -4 ; y = 14 và z = 9
b, \(-\frac{-10}{y}=\frac{x}{-9}=-1\frac{2}{3}=\frac{-z}{12}\)
\(\Rightarrow\) \(\frac{10}{y}=\frac{x}{-9}=\frac{-5}{3}=\frac{z}{-12}\)
\(\Rightarrow\) x = (-5)(-9) : 3 = 15 ; y = 10 . 3 : (-5) = -6 ; z = (-5)(-12) : 3 = 20
Vậy x = 15 ; y = -6 và z = 20
Chúc bn học tốt