Bài 5: Lũy thừa của một số hữu tỉ

a: =3^11/3^10=3

b: =2^6*3^7/2^6*3^6=3^7/3^6=3

c: \(=\dfrac{2^5\cdot2\cdot5^5}{10^5\cdot10}=\dfrac{2}{10}=\dfrac{1}{5}\)

d: \(=\dfrac{2^6\cdot7^6\cdot7}{2^6\cdot7^6}=7\)

a/ kq =\(\dfrac{3^{11}}{3^{10}}\)=3

b/kq = \(2^6\cdot3^6\cdot3\)/6^6 = 6^6 x 3 / 6^6 = 3

c/ kq = 2^5 x 5^5 X 2 / 10^5 x 10 = 1/5

d/ kq = 2^6 x 7^6 x 7 / 14^6 = 7

a) = (0,125*8)^3 = 1^3 = 3

b) = (-125)^4 : 25^5 = 125^4 : (5^2)^5 = (5^3)^4 : 5^10 = 5^12 : 5^10 = 5^2 = 25

c) =(-64:4)^5 = (-16)^5 = -1048576

d) = 81^6 : 3^6 = (81:3)^6 = 27^6 = 387420489

(0,125)^2 = (0,5^3)^2 = 0,5^6

(0,0625)^3 = (0,5^4)^3= 0,5^12

(0,125)^2=(0,5)^6

(0,0625)^3=(0,5)^12

\(\left(0,125\right)^2=\left(0,5^3\right)^2=0,5^6\)

\(\left(0,0625\right)^3=\left(0,5^4\right)^3=0,5^{12}\)

a: =>x=(-3/5)^5:(-3/5)^2=(-3/5)^3=-27/125

b: =>x=(-1/4)^3*(-1/4)=(-1/4)^4=1/256

`(1 1/4)^10 . (2/5)^20`

`=(5/4)^10 . (2/5)^20`

`=(5^10 .2^20)/(4^10 .5^20)`

`=(5^10 .4^10)/(4^10 .5^20)`

`=1/(5^10)`

`=(1/5)^10`

\(2^3+3^3=8+27=35\)

2^3+3^3=8+27=35

Vì \(\widehat{A} \) là góc tù `=>` Cạnh `BC` là cạnh lớn nhất

`=> BC > AC` 

Mà bán kính nghe rõ của loa là `500m`

`=>` Từ khoảng cách đó không thể nghe thấy được.

\(\dfrac{2.6^9-2^5.18^4}{2^2.6^8}\\ =\dfrac{2.\left(2.3\right)^9-2^5.\left(2.3^2\right)^4}{2^2.\left(2.3\right)^8}\\ =\dfrac{2.2^9.3^9-2^5.2^4.\left(3^2\right)^4}{2^2.2^8.3^8}\\ =\dfrac{2.2^9.3^9-2^5.2^4.3^8}{2^{10}.3^8}\\ =\dfrac{2^{10}.3^9-2^9.3^8}{2^{10}.3^8}\\ =\dfrac{2^9.3^8\left(2.3-1\right)}{2^{10}.3^8}\\ =\dfrac{6-1}{2}\\ =\dfrac{5}{2}\)

\(=\dfrac{5^6+5^6\cdot2^2+5^6\cdot2^3}{26\cdot5^6}=\dfrac{6^6\left(1+4+8\right)}{26\cdot5^6}=\dfrac{13}{26}=\dfrac{1}{2}\)