Bài 5: Hàm số

a.->-3->-5->-15->15->5->3->1
b.\(f\left(-3\right)=\dfrac{15}{-3}=-5\)
\(f\left(6\right)=\dfrac{15}{6}=\dfrac{5}{2}=2,5\)

\(a,\begin{matrix}x&-5&-3&-1&1&3\\y=f\left(x\right)&-3&-5&-15&15&5\end{matrix}\begin{matrix}5&15\\3&1\end{matrix}\\ b,f\left(-3\right)=\dfrac{15}{-3}=-5\\ f\left(6\right)=\dfrac{15}{6}=\dfrac{5}{3}\)

b: f(-3)=-5

f(6)=5/2

\(\Leftrightarrow x\left(x-2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)

a: f(2)=9

f(-1/4)=0

\(a,f\left(2\right)=8+1=9\\ f\left(-\dfrac{1}{4}\right)=4\left(-\dfrac{1}{4}\right)+1=-1+1=0\\ b,f\left(x\right)=13\Leftrightarrow4x+1=13\Leftrightarrow x=3\)

Câu 1: C

Câu 2: A

\(f\left(0\right)=0-0+1=1\\ f\left(-1\right)=3+4+1=8\\ f\left(\dfrac{1}{2}\right)=3.\dfrac{1}{4}-4.\dfrac{1}{2}+1=\dfrac{7}{4}\)

B.f(-1)=2

b: f(5)=15

f(-7/12)=-7/4