Question

y^3+y^2+4 . Phân tích đa thức thành nhân tử :((

Answer 1

\(=y^3+8+y^2-4\)

\(=\left(y+2\right)\left(y^2-2y+4\right)+\left(y+2\right)\left(y-2\right)\)

\(=\left(y+2\right)\left(y^2-y+2\right)\)

Answer 2

y³+y²+4

=y³+y²+4+4y-4y

=(y³-4y)+(y²+4y+4)

=y (y²-4)+(y+2)²

=y (y-2)(y+2)+(y+2)²

=(y+2)[y(y-2)+y+2]

=(y+2)(y²-2y+y+2)

=(y+2)(y²-y+2)