MA = \(\dfrac{64.100\%}{80\%}\)= 80
⇒ CTHH CuO
Ta có:
\(\dfrac{64\cdot x}{64\cdot x+16y}\cdot100=80\)\(\Leftrightarrow\dfrac{x}{4\cdot x+y}=\dfrac{1}{5}\)\(\Leftrightarrow x=\dfrac{4\cdot x+y}{5}\) (1)
\(\dfrac{16\cdot y}{64\cdot x+16y}\cdot100=20\)\(\Leftrightarrow\dfrac{y}{4\cdot x+y}=\dfrac{1}{5}\)\(\Leftrightarrow y=\dfrac{4\cdot x+y}{5}\) (2)
Từ (1), (2) \(\Rightarrow\) x : y = 1 : 1
CTHH: CuO