Question

(x+4)(x²-4x+16)

(x-3y)(x²+3xy+9y²)

(x²-\(\dfrac{1}{3}\))(x⁴+\(\dfrac{1}{3}\)x²+\(\dfrac{1}{9}\))

Answer 1

\(=x^3+64\\ =x^3-27y^3\\ =x^6-\dfrac{1}{27}\)

Answer 2

\(\left(x+4\right)\left(x^2-4x+16\right)=x^3+64\)

\(\left(x-3y\right)\left(x^2+3xy+9y^2\right)=x^3-27y^3\)

\(\left(x^2-\dfrac{1}{3}\right)\left(x^4+\dfrac{1}{3}x^2+\dfrac{1}{9}\right)=x^6-\dfrac{1}{27}\)