Question

x² – y² + xz - yz

Answer 1

\(x^2-y^2+xz-yz\)

\(=\left(x-y\right)\left(x+y\right)+z\left(x-y\right)\)

\(=\left(x-y\right)\left(x+y+z\right)\)

Answer 2

= (x-y)(x+y) + z(x-y) = (x-y)(x+y+z)

Answer 3

\(x^2-y^2+xz-yz\)

Đề : Phần tích đa thức thành nhân tử

\(\left(x^2-y^2\right)+\left(xz-yz\right)\)

\(=\left(x-y\right)\left(x+y\right)+z\left(x-y\right)\)

\(=\left(x-y\right)\left(x+y+z\right)\)