{ x2 - [ 62 - ( 82 -9.7 )3 -7.5 ]3 -5.3 }3 =1 ... {x2 - [62 - 13 -7.5]3 - 5.3}3=1. {x2 - [36 - 1 -7.5]3 - 5.3}3=1. {x2 - [36 - 1 - 35]3 - 5.3}3=1. {x2 - [35 - 35]3 -5.3}3=1. {x2 - 03 - 5.3}3=1. {x2 - 0 -5.3}3=1. {x2 - 0 - 15}3=1. {x.x - 0 - 15}3=1. {x.x + 0+15}3=1. {x.x +15}3=1.
{x mũ 2 - [6 mũ 2 - (8 mũ 2 - 9.7) mũ 3 - 7.5] mũ 3 - 5.3} mũ 3 = 1
tính
a,8.6+288:(x-)^2=50
b,{x^2-[6^2-(8^2-9.7)^3-7.5]^3-5.3)^3=1^3
tìm x biết {x2-[62-(82-9.7)37.5)3-5.33} = 1
Tìm x:
{x2-[62(82-9.7)3-7.5]3-5.3}3=1
tim so tu nhien x biet rang
(X2-(62-(82-9.7)3-7.5)3-5.3)3=1
{ x 2 - [ 6 2 - ( 8 2 - 9.7 ) 3 -7.5 ] 3 - 5.3 }3 =5
{ x2 - [ 62 - ( 82 - 9.7 )3 - 7.5 ]3 - 5.3 }3 = 1
giúp vs ạ
{x2 - [62 - (82 - 9.7)3 - 7.5]3 - 5.3}3 = 1
{ x2 - [ 62 - ( 82 - 9.7 )3 - 7.5 ]3 - 5.3 }3 = 1
Mong mọi ng giúp ạ....
