Các câu hỏi tương tự
Tìm x:
\(\frac{x+1}{2019}+\frac{x+2}{2017}+\frac{x+3}{2016}=\frac{x+10}{2010}+\frac{x+11}{2009}+\frac{x+12}{2008}\)
x+1/2009+x+2/2008+x+3/2007=x+10/2000+x+11/1999+x+12/1998
tìm x
x+1/2009 + x+2/2008 + x+3/2007 + x=10/2000 + x==11/1999 + x+12/1998
Tìm x,biết:
a,3 / (x+2).(x+5) + 5 / (x+5).(x+10) + 7 / (x+10) . (x+17)= x / (x+2).(x+17)
x∉{-2 ; -5 ;-10 ; -17}
b,2 / (x-1). (x-3)+5 / (x-3).(x-8)+12 / (x-8).(x-20)-1 / x-20=-3/4
x∉{1;3;8;20}
c,x-1/2009 + x-2/2008 = x-3/2007 + x-4 / 2006
Tìm x
a/\(\frac{x+7}{2003}+\frac{x+4}{2006}=\frac{x-1}{2011}+\frac{x-5}{2015}\)
b/\(\frac{x-1}{2009}+\frac{x-2}{2008}=\frac{x-3}{2007}+\frac{x-4}{2006}\)
c/\(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
TÍNH
A,|X-3 Y|^2007+|Y+4|^2008
B,(X+Y)^2016+2017.|Y-1|
(4-x).(2x+1/3)=(2006/2007-2007/2008+2008/2009).(2/3-1/4-5/12)
giúp mình nhé thank nhiều :D
(x-1/2009)+(x-2/2008)=(x+3/2007)+(x+4/2006)
x-1/2009 + x-2/2008 = x-3/2007 + x-4/2006