A=\(x^{10}-10x^9+10x^8-...-10x+10\)
=\(x^{10}-9x^9-x^9+9x^8+x^8-....-9x-x+10\)
= \(x^9\left(x-9\right)-x^8\left(x-9\right)+x^7\left(x-9\right)-...-\left(x-9\right)+1\)
= \(\left(x-9\right)\left(x^9-x^8+x^7-...-1\right)+1\)
Thay x=9 ta được :
A= \(0\left(x^9-x^8+x^7-...-1\right)+1=1\)
Vậy A=1