Question

(x-\(\dfrac{1}{5}\))²=\(\dfrac{4}{25}\)

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Answer 1

\(\left(x-\dfrac{1}{5}\right)^2=\dfrac{4}{25}\Leftrightarrow\left(x-\dfrac{1}{5}\right)^2=\left(\dfrac{2}{5}\right)^2\)

\(\Leftrightarrow x-\dfrac{1}{5}=\dfrac{2}{5}\Leftrightarrow x=\dfrac{3}{5}\)

Answer 2

pt \(\Leftrightarrow\)\(\left[{}\begin{matrix}x-\dfrac{1}{5}=\dfrac{2}{5}\\x-\dfrac{1}{5}=-\dfrac{2}{5}\end{matrix}\right.\)\(\Leftrightarrow\)\(\left[{}\begin{matrix}x=\dfrac{3}{5}\\x=-\dfrac{1}{5}\end{matrix}\right.\)

Answer 3

\(\left(x-\dfrac{1}{5}\right)^2=\dfrac{4}{25}\)

\(\Rightarrow\left(x-\dfrac{1}{5}\right)^2=\left(\pm\dfrac{2}{5}\right)^5\)

\(\Rightarrow\left[{}\begin{matrix}x-\dfrac{1}{5}=\dfrac{2}{5}\\x-\dfrac{1}{5}=-\dfrac{2}{5}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}+\dfrac{1}{5}=\dfrac{3}{5}\\x=-\dfrac{2}{5}+\dfrac{1}{5}=\dfrac{-1}{5}\end{matrix}\right.\)

Vậy \(x=\dfrac{3}{5}\) hoặc \(x=\dfrac{-1}{5}\)