$x+2> x-2$ nên đề sai. Bạn xem lại đề.
Đúng 0
Bình luận (0)
Các câu hỏi tương tự
B1:tìm x biết a, (-2+x^2)(x^2-2)(x^2-2)(x^2-2)(x^2-2)=1 b, (2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4) c,(8x-3)(3x+2)-(4x+7)(x+4)=(4x+1)(5x-1) d, 2x^2+3(x-1)(x+1)=5x(x+1) e, (8-5x)(x+2)+4(x-2)(x+1)=(2+x)(2-x) f, 4(x-1)(x+5)-(x+2)(x+5)=3(x-1)(x+2)
Bài 1:
a, (-2+x\(^2\))(x\(^2\)-2)(x\(^2\)-2)(x\(^2\)-2)(x\(^2\)-2)=1
b, (2x+3)(x-4)+(x-5)(x-2)=(3x-5)(x-4)
c, (8x-3)(3x+2)-(4x+7)(x+4)=(4x+1)(5x-1)
d,2x\(^2\)+3(x-1)(x+1)=5x(x+1)
e,(8-5x)(x+2)+4(x-2)(x+1)=(2+x)(2-x)
f, 4(x-1)(x+5)-(x+2)(x+5)=3(x-1)(x+2)
.A) x/x+1=1/2 , B) x/2=x/3 , C) x+1/2=x+1/2017, i)3/x=x/2017 , O) x:3=x+1/2 , m) x+1/2=x+2/3 ,P) x+1/2=x , M) 2/x=x/8 , Q) x2/2=8/x2 , r) x3/2=32/x
1)x^2.(2x^3-x^2+4x) 2)(x+2).(5x^3-3x^2+x) 3)(x^2-2).(x^2+2x-1) 4)(x^2+x+1).(x-1)
(x+3)x+1=(x+3)x+2
(x-1)x+=(x-1)x+2
(2x-1)2=(x-3)2
Xem chi tiết
A(x)=x^2 -3x+1-x^2
B(x)=6-1/3x
C(x)=x^2+2x
D(x)=4x^2-1
E(x)=2x^2+3x
G(x)=(-x+1) (x^2-1)
H(x)=9x^3-4x
k(x)=x^3+x
A(x)=x^2 -3x+1-x^2
B(x)=6-1/3x
C(x)=x^2+2x
D(x)=4x^2-1
E(x)=2x^2+3x
G(x)=(-x+1) (x^2-1)
H(x)=9x^3-4x
k(x)=x^3+x
câu 1 Phân tích các đa thức sau thành nhân tử a, (1+2x).(1-2x) -x(x+2)(x-2) ; b, x^2+y^2-x^2y^2+xy-x-y; c, 2x^2(x+1)-x+1; câu 2 : Tìm x, biết : a, x^3-36x=0; b, ( 3x-1)^2=( x+3)^2; c, x^2(x-1)-4x^2+8x-4=0
Bài 1. Tìm x.a) -5(x2-3x+1)+x
(1+5x)x-2b) 12x2-4x(3x+5)10x-17c) -4x(x-5)+7x(x-4)-3x212Bài 2. Tính ( Rút gọn).a) (x+5).(x-7)-7x.(x-3)b) x.(x2-x-2)-(x-5).(x+1)c) (x-5).(x-7)-.(x+4).(x-3)d) (x-1).(x-2)-(x+5).(x+2)
Đọc tiếp
Bài 1. Tìm \(x\).
a) -5(\(x\)2-3\(x\)+1)+\(x \)(1+5\(x\))=\(x-2\)
b) \(12x\)2\(-4x\)\((3x+5)\)\(=10x-17\)
c) \(-4x(x-5)+7x(x-4)-3x\)2\(=12\)
Bài 2. Tính ( Rút gọn).
a) \((x+5).(x-7)-7x.(x-3)\)
b) \(x.(x\)2\(-x-2)-(x-5).(x+1)\)
c) \((x-5).(x-7)-.(x+4).(x-3)\)
d) \((x-1).(x-2)-(x+5).(x+2)\)
Tìm x biết : a ) x+2/5= 1/x-2 b ) x/x+1=x+5/x+7 c )x-1/x+2=x-2/x+3