Question

viet cac bthuc sau duoi dang tich

a) x^4+4x^2+4

 9a^4+24a^2b^2+16b^4

b)4a^2b^2-c^2d^2

 a^3+27

x^16-y^16

c)x^3 -125

-64+1/8x^3

d)8x^3+60x^2y+150xy^2+125y^3

Answer 1

a: \(=\left(x^2+2\right)^2\)

\(=\left(3a^2+4b^2\right)^2\)

b: \(=\left(2ab-cd\right)\left(2ab+cd\right)\)

\(=\left(a+3\right)\cdot\left(a^2-3a+9\right)\)

c: \(x^3-125=\left(x-5\right)\left(x^2+5x+25\right)\)

Answer 2

 

a, \(=\left(x^2+2\right)^2\)

b, \(=\left(3a^2+4b^2\right)^2\)

\(=\left(2ab-cd\right)\left(2ab+cd\right)\)

\(=\left(a+3\right)\left(a^2-3a+9\right)\)

 \(x^{16}-y^{16}=\left(x^4-y^4\right)\left(x^4+y^4\right)=\left(x-y\right)\left(x+y\right)\left(x^2+y^2\right)\left(x^4+y^4\right)\)

c, \(=\left(x-5\right)\left(x^2+5x+25\right)\)

\(=-\left(4-\dfrac{1}{2}x\right)\left(16+2x+\dfrac{1}{4}x^2\right)\)

d, \(=\left(2x+5y\right)^3\)