\(m_{Fe_2O_3}=100000.80\%=80000(kg)\\ \Rightarrow n_{Fe_2O_3}=\dfrac{80000}{160}=500(kmol)\\ PTHH:Fe_2O_3+3CO\xrightarrow{t^o}2Fe+3CO_2\\ \Rightarrow n_{Fe}=2n_{Fe_2O_3}=1000(kmol)\\ \Rightarrow m_{Fe}=1000.56=56000(kg)\\ \Rightarrow m_{Fe(\text {Thực tế})}=56000.60\%=33600(kg)=33,6(tấn)\)