\(\sqrt{8-3\sqrt{7}}-\sqrt{8+3\sqrt{7}}=\frac{\sqrt{16-6\sqrt{7}}-\sqrt{16+6\sqrt{7}}}{\sqrt{2}}\)
\(=\frac{\sqrt{\left(\sqrt{7}-3\right)^2}-\sqrt{\left(\sqrt{7}+3\right)^2}}{\sqrt{2}}=\frac{3-\sqrt{7}-\left(\sqrt{7}+3\right)}{\sqrt{2}}\)
\(=\frac{-2\sqrt{7}}{\sqrt{2}}=-\sqrt{14}\)