Question

\(Tính.nhanh.các.tổng.sau:\)

\(\dfrac{\dfrac{19}{17}-\dfrac{100}{49}+\dfrac{129}{131}}{\dfrac{3}{17}-\dfrac{3}{49}-\dfrac{3}{131}}\)

\(giải.chi.tiết\)

Answer 1

=>

\(\dfrac{19}{17}-\dfrac{100}{49}+\dfrac{129}{131}=\dfrac{3}{17}-\dfrac{3}{49}-\dfrac{3}{131}\)

<=>

\(\dfrac{19}{17}-\dfrac{100}{49}+\dfrac{129}{131}-\dfrac{3}{17}+\dfrac{3}{49}+\dfrac{3}{131}=0\)

<=>

\(\dfrac{19}{17}-\dfrac{3}{17}-\dfrac{100}{49}+\dfrac{3}{49}+\dfrac{129}{131}+\dfrac{3}{131}=0\)

<=>

\(\dfrac{16}{17}-\dfrac{103}{49}+\dfrac{132}{131}=\) sao nó ra âm - 0 luoon kì v ta:<

Answer 2

19/17-100/49+129/131 / 3/17-3/49-3/131

=19/3-100/3+43/1 / 1

=19/3-100/3+129/3 / 1

= ( 19/3+129/3 ) - 100/3 / 1

=148/3 - 100/3 / 1

=48/3 / 1

= 16