Question

Tính a.(√2/3+√50/3-√24)√6 b.(√3/4-√3+5√4/3)√12 c.(√1/7-√16/7+√7):√7 d.(√1/3-√4/3+√3):√3

Answer 1

a: \(=\left(\dfrac{1}{3}\sqrt{6}+\dfrac{5}{3}\sqrt{6}-2\sqrt{6}\right)\cdot\sqrt{6}\)

\(=\left(2\sqrt{6}-2\sqrt{6}\right)\cdot\sqrt{6}\)

=0

b: \(=\left(\dfrac{1}{2}\sqrt{3}-\sqrt{3}+5\cdot\dfrac{2\sqrt{3}}{3}\right)\cdot2\sqrt{3}\)

\(=\dfrac{17}{6}\sqrt{3}\cdot2\sqrt{3}=17\)

c: \(=\dfrac{\left(\dfrac{1}{7}\sqrt{7}-\dfrac{4}{7}\sqrt{7}+\sqrt{7}\right)}{\sqrt{7}}\)

=1/4-4/7+1

=1-3/7=4/7