Question

Tính tổng:

\(S=\frac{27+4500+135+550.2}{2+4+6+...+14+16+18}\)

Answer 1

\(S=\frac{27+4500+135+550.2}{2+4+6+...+14+16+18}\)

\(S=\frac{4527+135+1100}{\left(2+18\right).9:2}=\frac{4662+1100}{20.9:2}=\frac{5762}{90}=\frac{2881}{45}\)

Answer 2

\(B=\frac{27+4500+135+1100}{\frac{\left(2+18\right).9}{2}}=\frac{5762}{10.9}=\frac{2881}{45}\)

Answer 3

2881/45

Answer 4

\(s=\frac{27+4500+135+550×2}{2+4+6+.....+18}\)

\(s=\frac{4527+135+1100}{\left(2+18\right)×9:2}\)

\(s=\frac{1662+1100}{20×9:2}\)

\(s=\frac{2881}{45}\)

Answer 5

2881/45