a: =(329-329)+64+36=100
b: =(-464+564)+(-371+71)
=100-300=-200
Ta có
329 + 64 + (–329) + 36
= (329 – 329) + (64 + 36)
= 0 + 100
= 100
\(329+64+(-329)+36\)
\(= [ 329 + ( − 329 ) ] + ( 64 + 36 )\)
\(= 0 + 100 = 100\)
\(--------------\)
\((-464)+(-371)+564+71\)
\(= [ ( − 464 ) + 564 ] + [ ( − 371 ) + 71 ]\)
\(= 100 + ( − 300 ) = − 200\)
a.329+64+(-329)+36
= [ 329 + (-329) ] + ( 64 + 36 )
= 0 + 100
= 100
b.(-464)+(-371)+564+71
= [ (-464) + 564 ] + [ (-371) + 71 ]
= 100 + ( -300 )
= -200