Ta có:
`hat{A} + hat{B} + hat{C} + hat{D} = 360^o`
`=> 120^o + 90^o + hat{C} + hat{D} = 360^o`
`=> hat{C} + hat{D} = 150^o`
Mà `hat{C} = 2 hat{D}`
Nên: `2 hat{D} + hat{D} = 150^o`
`=> 3hat{D} = 150^o`
`=> hat{D} = 50^o`
Khi đó: `hat{C} = 100^o`
Vậy ..
Xét tứ giác ABCD có:
\(\widehat{A}+\widehat{B}+\widehat{C}+\widehat{D}=360^o\)
\(\Rightarrow120^o+90^o+\widehat{C}+\widehat{D}=360^o\)
\(\Rightarrow\widehat{C}+\widehat{D}=150^o\)
mà \(\widehat{C}=2\widehat{D}\)
\(\Rightarrow2\widehat{D}+\widehat{D}=150^o\)
\(\Rightarrow\widehat{D}=50^o\)
\(\Rightarrow\widehat{C}=2\cdot50^o=100^o\)