\(A=\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+...+\frac{1}{99\cdot100}\)
\(A=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{99}-\frac{1}{100}\)
\(A=\frac{1}{3}-\frac{1}{100}\)
\(A=\frac{97}{300}\)
dễ nhưng mình đang bận , chúc ban học tốt , k mình nha hihi
A = \(\frac{1}{12}+\frac{1}{20}+...+\frac{1}{9900}\)
A = \(\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{99.100}\)
A = 1/3 - 1/4 + 1/4 - 1/5 + ... + 1/99 - 1/100
A = 1/3 - 1/100
A = 97/300
Ta có :
\(A=\frac{1}{12}+\frac{1}{20}+...+\frac{1}{9900}\)
\(\Rightarrow A=\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{99.100}\)
\(\Rightarrow A=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{99}-\frac{1}{100}\)
\(\Rightarrow A=\frac{1}{3}-\frac{1}{100}\)
\(\Rightarrow A=\frac{100}{300}-\frac{3}{100}\)
\(\Rightarrow A=\frac{97}{100}\)
~ Ủng hộ nhé
\(A=\frac{1}{12}+\frac{1}{20}+....+\frac{1}{9900}\)
\(A=\frac{1}{3.4}+\frac{1}{4.5}+....+\frac{1}{99.100}\)
\(A=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+.....+\frac{1}{99}-\frac{1}{100}\)
\(A=\frac{1}{3}-\frac{1}{100}\)
\(A=\frac{97}{300}\)
\(A=\frac{1}{12}+\frac{1}{20}+...+\frac{1}{9900}\)
\(A=\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+...+\frac{1}{99\cdot100}\)
\(A=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{99}-\frac{1}{100}\)
\(A=\frac{1}{3}-\frac{1}{100}\)
\(A=\frac{100}{300}\)\(-\frac{3}{300}\)
\(A=\frac{97}{300}\)
\(A=\frac{1}{12}+\frac{1}{20}+...+\frac{1}{9900}\)
\(\Rightarrow A=\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{99.100}\)
\(\Rightarrow A=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{99}-\frac{1}{100}\)
\(\Rightarrow A=\frac{1}{3}-\frac{1}{100}\)
\(\Rightarrow A=\frac{97}{300}\)